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KT
Joined: 02 Dec 2007
Posts: 7
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 Posted: Sun Dec 02, 2007 4:42 am Post subject: Math Help -- PLEASE? |
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| Find the length of the 3rd side of the right triangle. assume that c represents the length of the hypotenuse. Give an exact answer and if appropriate, an approximation to 3decimal places.a = 7, b = 24 C??????? (i need to show work done out so i can teach myself)Also -- Sam consumed 2162 calories on monday , 2334 cals on tues and 1869 cals on wed. His avg. daily intake is 2100 how many cals. of food must he consume on Thursday? |
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CHRY
Joined: 02 Dec 2007
Posts: 4
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| Posted: Sun Dec 02, 2007 4:54 am Post subject: Math Help -- PLEASE? |
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| doa square + b square = c square....tha pathagraem theom or however the hell u spell it.....i think....but im not sure im in the 9th grade and have a c in algerbra soooo yeah...lolthats probably wrong. |
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Baseball26
Joined: 02 Dec 2007
Posts: 1
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| Posted: Sun Dec 02, 2007 5:06 am Post subject: Math Help -- PLEASE? |
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| use a^2+b^2=C^249+841=890sq root =29.832867 |
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sandeepV
Joined: 02 Dec 2007
Posts: 11
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| Posted: Sun Dec 02, 2007 5:18 am Post subject: Math Help -- PLEASE? |
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| no need to math homework and school work becouse when you not take interest in this subject you can not able those ques easily so that please try to make first interst in math and put up your problem from math guru |
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soccer4ever
Joined: 02 Dec 2007
Posts: 16
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| Posted: Sun Dec 02, 2007 5:30 am Post subject: Math Help -- PLEASE? |
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| a^2 + b^2=c^27^2+ 24^2=c^249+576=625take the square root of 625 and its 25 |
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whatisavavailable
Joined: 02 Dec 2007
Posts: 3
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| Posted: Sun Dec 02, 2007 5:42 am Post subject: Math Help -- PLEASE? |
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| This is for the first problem one you have to use pythagorem's theorm. if the triangle is a right triangle then you know that a squared + b squared = c squared . so (7 X 7) + (24 X 24) = ( c X c)once you find the left side of the equasion you take the square root on each side to get rid of the c squared. |
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heartbreaker
Joined: 02 Dec 2007
Posts: 1
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| Posted: Sun Dec 02, 2007 5:54 am Post subject: Math Help -- PLEASE? |
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| right triangles require the pythagorean theorom:"a" squared + "b" squared = "c" squaredsoo....for your situation flip the equaton around to "c" = the square root of ("a" squared + "b" squared)yea that's more than enough math for me for one night...somebody else can help you out with that second one. |
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diverdownbelow0792
Joined: 02 Dec 2007
Posts: 2
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| Posted: Sun Dec 02, 2007 6:06 am Post subject: Math Help -- PLEASE? |
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| a sq + b sq = c sq49 + 576=625 = c sqsq root of c sq = 252162 + 2234 + 1869 + x = 2100*4days = 84008400 - 2162-2234-1869=xx=2135 |
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Heinz
Joined: 02 Dec 2007
Posts: 3
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| Posted: Sun Dec 02, 2007 6:18 am Post subject: Math Help -- PLEASE? |
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| so a^2 + b^2 = c^27^2 + 24^2 = c^249 + 576 = c^2625 = c^2c=25so 2162+ 2334+ 1869 + x / 4 = 21006365 + x = 8400x= 2035so he must consume 2035 calories on wed |
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ModelDanceSingFightFire
Joined: 02 Dec 2007
Posts: 1
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| Posted: Sun Dec 02, 2007 6:30 am Post subject: Math Help -- PLEASE? |
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| you do 2100 times 4 because thats the number or days this will be 8400then you add up monday tuesday and wednesdays2162+ 2334+ 1869= 6365Next you subtract 6365 from 8400 which is 2035So on thursday he had 2035 caloriesi'm not sure about the first one but if u go to www.hotmath.com they may have the solution there. |
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Momo
Joined: 02 Dec 2007
Posts: 2
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| Posted: Sun Dec 02, 2007 6:42 am Post subject: Math Help -- PLEASE? |
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| a^2 + b^2 = c^27^2 + 24^2 = c^2(7x7) + (24x24) = c^249 + 576 = 625 625= c^2 but since you are looking for just c you have to solve for cso you just *quare root*25=c |
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BROBEAST
Joined: 02 Dec 2007
Posts: 2
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| Posted: Sun Dec 02, 2007 6:54 am Post subject: Math Help -- PLEASE? |
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| Problem 1:-7 squared= 49-24 squared= 576-49+576= 625-Square Root of 625= 25-side c = 25Problem 2: 2035you multiply 2100 by 4 and subtract the amounts from monday - wednessday and are left with thursday's amount |
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Rachie
Joined: 02 Dec 2007
Posts: 25
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| Posted: Sun Dec 02, 2007 7:06 am Post subject: Math Help -- PLEASE? |
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| I will try to help you without providing you with the whole answer. You will have to do the math work, but I will give you the steps to use. Use the pythagoreum theorum for the first problem: a ^2 + b^2 = c^2. So you will have 7^2 + 24^2 = c^2Add 7^2 and 24^2 together. then take the square root of that sum in order to find C.For the second problem: Make an equation:Add Monday-Wednesday calories consumed together. Put that sum and add (x) to represent Thursday's calorie count. Then divide all of that by four because there are four days counted in the average. On the other side of the equal sign, put 2100.It will look like this (MWF calories + x) / 4 = 2100.Then balance the equation and find the value of x. Multiply both sides by four. Then subtract the MWF sum of calories from both sides. You will then have the value of x, which is the number of calories eaten on Thursday. |
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